Hydra: Difference between revisions

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starting from <math>C(3,0)</math>, using configurations of the form <math>C(a+2,b) = 0^\infty \; <B \; 0^{3a} \; 3^b \; 2 \; 0^\infty</math>.<ref>S. Ligocki, "[https://www.sligocki.com/2024/05/10/bb-2-5-is-hard.html BB(2, 5) is Hard (Hydra)] (2023). Accessed 22 July 2024.</ref>
starting from <math>C(3,0)</math>, using configurations of the form <math>C(a+2,b) = 0^\infty \; <B \; 0^{3a} \; 3^b \; 2 \; 0^\infty</math>.<ref>S. Ligocki, "[https://www.sligocki.com/2024/05/10/bb-2-5-is-hard.html BB(2, 5) is Hard (Hydra)] (2024). Accessed 22 July 2024.</ref>


It is closely related to the machine [[Antihydra]].<ref>S. Ligocki, "[https://www.sligocki.com/2024/07/06/bb-6-2-is-hard.html BB(6) is Hard (Antihydra)]" (2024). Accessed 22 July 2024.</ref>
It is closely related to the machine [[Antihydra]].<ref>S. Ligocki, "[https://www.sligocki.com/2024/07/06/bb-6-2-is-hard.html BB(6) is Hard (Antihydra)]" (2024). Accessed 22 July 2024.</ref>

Revision as of 07:43, 3 October 2024

Unsolved problem:
Does Hydra run forever?

1RB3RB---3LA1RA_2LA3RA4LB0LB0LA (bbch)

Hydra is a BB(2,5) machine that simulates the Collatz-like iteration


starting from , using configurations of the form .[1]

It is closely related to the machine Antihydra.[2]

The sequence calculated by Hydra is a consistent Collatz sequence, (which implies, among other things, that its odd/even pattern can be calculated in quasilinear time). In the first 60 million elements, there are 29995836 even values of a and 30004165 odd values; thus, is known that Hydra cannot halt within the first 90 million Collatz iterations.

An older simulator for the odd/even sequence used by Hydra is available here, but it runs in time and thus is unusably slow compared to the consistent Collatz simulation approach.

Name

The name Hydra references the Ancient Greek legend: just as the legendary creature was growing 2 heads after losing 1 head, the b counter that is kept on the right side of the tape either increases by 2 or decreases by 1 (approximately with equal frequency if modelled as a random process; in reality it depends on the parity of a). The Hydra dies (halts) when the last head is cut.

Sources

  1. S. Ligocki, "BB(2, 5) is Hard (Hydra) (2024). Accessed 22 July 2024.
  2. S. Ligocki, "BB(6) is Hard (Antihydra)" (2024). Accessed 22 July 2024.