User:Polygon/Page for testing: Difference between revisions

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{machine|1RB1LE_1LB1LC_1RD0LE_---0RB_1RF1LA_0RA0RD}}
List of incomplete pages:
{{TM|1RB1LE_1LB1LC_1RD0LE_---0RB_1RF1LA_0RA0RD}} is a [[BB(6)]] [[holdout]] TM.
* [[Coq-BB5]]
* [[Finite Automata Reduction]]
* [[CTL]]
* [[Irregular Turing Machine]]
* [[Meet-in-the-Middle Weighted Finite Automata Reduction (MITMWFAR)]]
* [[Skelet 1]]
* [[CPS]] (CPS_LRU, CPS_LRUH)


==Analysis==


Early rules:
* [[Repeated Word List]] (RWL_mod; more detailed description for RWLAcc)
<pre>
S is any tape configuration


1. S 0^a <B S --> S <B 1^a S [+a steps]
== 1RB2LA1RC3RA_1LA2RA2RB0RC_1RZ3LC1RA1RB ==
2. S D> 1^2 S --> S 1 D> 1 S [+3 steps]
3. S D> 1^a 1 S --> S 1^a D> 1 S [+3a steps] (if a > 0)
4. S (11)^a <E S --> S <E (11)^a S [+2a steps]
  S (11)^a <A S --> S <A (11)^a S [+2a steps]
5. S 1^2 D> 1 0 S --> S <E 0 1^3 S [+5 steps]
6. S 0 1^a <E S --> S 1 0 1^a-2 D> 1 S [+4a -4 steps] (if a mod 2 = 0)
</pre>


Later rules:
{{machine|1RB2LA1RC3RA_1LA2RA2RB0RC_1RZ3LC1RA1RB}
<pre>
{{TM|1RB2LA1RC3RA_1LA2RA2RB0RC_1RZ3LC1RA1RB} is a non-halting [[BB(4,3)]] TM discovered by Pavel Kropitz in May 2023.<ref>https://discord.com/channels/960643023006490684/1095740122139480195/1113545691994783804</ref In April 2024, Shawn Ligocki showed the TM to follow an infinite pentational rule, proving it non-halting.<ref>https://discord.com/channels/960643023006490684/1095740122139480195/1230591736829575282</ref
Let A(a, b, c, d, e, f, ..., k) = 0^inf 1^a 0 1^b D> 1 0 1^c 0 1^d 0 1^e 0 1^f ... 0 1^k 0^inf


b mod 2 = 0:
=== Analysis by Shawn Ligocki ===
  b ≥ 4: A(a, b, c, ...) --> A(a+1, b-4, c+3, ...)
https://discord.com/channels/960643023006490684/1095740122139480195/1230591736829575282
  b = 2: A(a, 2, c, d, ...) --> A(a+2, c+1, d, ...)
  b = 0:
      a mod 2 = 0:
        a ≥ 4: A(a, 0, c, ...) --> A(1, a-4, c+4, ...)
        a = 2: A(2, 0, c, d, ...) --> A(2, c+2, d, ...)
        a = 0: A(0, 0, c, ...) --> spin out
      a mod 2 = 1:
        a ≥ 4: A(a, 0, c, ...) --> A(2, a-4, c+4, ...)
        a = 3: A(3, 0, c, ...) --> halt with 0^inf 1^2 0 1 Z> 1^c+4 ...
        a = 1: A(1, 0, c, d, ...) --> A(0, c+4, d, ...)
b mod 2 = 1:
  b ≥ 3:
      a mod 2 = 0:
        a ≥ 2: A(a, b, c, ...) --> A(1, a-2, b-2, c+3, ...)
        a = 0:
            b ≥ 5: A(0, b, c, ...) --> A(2, b-4, c+3, ...)
            b = 3: A(0, 3, c, ...) --> halt with 0^inf 1^2 0 1 Z> 1^c+3 ...
      a mod 2 = 1:
        a ≥ 2: A(a, b, c, ...) --> A(2, a-2, b-2, c+3, ...)
        a = 1: A(1, b, c, ...) --> halt with 0^inf 1^2 0 1 Z> 1^b-2 0 1^c+3 ...
  b = 1: A(a, 1, c, d, ...) --> A(0, a+c+3, d, ...)
</pre>
A(0, 0, c, ...), A(0, 3, c, ...) and A(1, 2k+1, c, ...) are not reachable by any of these rules (reaching them would require negative entries), meaning that they can only be triggered if they are the TMs starting configurations.


'''Accelerated rules:'''
<pre>
<pre>
R8: A(a, 4k+v, c, ...) --> A(a+k, v, c+3k, ...) [+4bk -8k^2 +k steps] (if v mod 2 = 0 and k ≥ 1)
Let D(a, b, c, d, e) = 0^inf 1 2^a 1 3^b 1 01^c 1 2^d <A 2^2e+1 0^inf
 
A1: A(0, 2k+1, c, ...) --> A(0, 2(k-1)+1, c+6, ...) [+16k +10 steps] (if k ≥ 3)
by:
A(0, 2k+1, c, ...)
--> A(2, 2(k-2)+1, c+3, ...) [+8k +3]
--> A(1, 0, 2(k-3)+1, c+6, ...) [+10k +10]
--> A(0, 2(k-1)+1, c+6, ...) [+16k +10]
 
A2: A(0, 2k+1, c, ...) --> A(0, 5, c+6k-12) [+8k^2 +18k -68 steps] (if k ≥ 3)
by repetition of rule A1


A3: A(0, 2k+1, c, ...) --> A(0, c+6k-4, ...) [+8k^2 +36k +3c -65 steps] (if k ≥ 3)
Level 1: D(a, b, c, 2k+r, e)  ->  D(a, b, c, r, e+2k)
by:
Level 2: D(a, b, c, 1, e) -> D(a, b, 0, 1, f2(c, e))
A(0, 2k+1, c, ...)
  where f2(c, e) = rep(λx -> 2x+5, c)(e) ~= 2^c
--> A(0, 5, c+6k-12, ...) by rule A2 [+8k^2 +18k -68]
Level 3: D(a, b, 0, 1, e) -> D(a, 0, 0, 1, f3(b, e))
--> A(2, 1, c+6k-9, ...) [8k^2 +18k -49]
  where f3(b, e) = rep(λx -> f2(x+2, 1), b)(e) ~= 2^^b
--> A(0, c+6k-4, ...) [+8k^2 +36k + 3c -65]
Level 4: D(2a+r, 0, 0, 1, e)  -> D(r, 0, 0, 1, f4(a, e))
</pre>
  where f4(a, e) = rep(λx -> f3(2x+7), a)(e) ~= 2^^^a
Level 5: D(0, 0, 0, 1, e)  -> D(0, 0, 0, 1, f4(4e+19, f3(1, 1)))


'''Using the accelerated rules:'''


<pre>
where the last rule repeats forever.
Let A(a, b, c, d, e, f, ..., k) = 0^inf 1^a 0 1^b D> 1 0 1^c 0 1^d 0 1^e 0 1^f ... 0 1^k 0^inf
 
b mod 2 = 0:
  b ≥ 4: A(a, 4k+v, c, ...) --> A(a+k, v, c+3k, ...)
  b = 2: A(a, 2, c, d, ...) --> A(a+2, c+1, d, ...)
  b = 0:
      a mod 2 = 0:
        a ≥ 4: A(a, 0, c, ...) --> A(1, a-4, c+4, ...)
        a = 2: A(2, 0, c, d, ...) --> A(2, c+2, d, ...)
        a = 0: unreachable
      a mod 2 = 1:
        a ≥ 4: A(a, 0, c, ...) --> A(2, a-4, c+4, ...)
        a = 3: A(3, 0, c, ...) --> halt with 0^inf 1^2 0 1 Z> 1^c+4 ...
        a = 1: A(1, 0, c, d, ...) --> A(0, c+4, d, ...)
b mod 2 = 1:
  b ≥ 3:
      a mod 2 = 0:
        a ≥ 2: A(a, b, c, ...) --> A(1, a-2, b-2, c+3, ...)
        a = 0:
            b ≥ 7: A(0, 2k+1, c, ...) --> A(0, c+6k-4, ...) by rule A3
            b = 5: A(0, b, c, ...) --> A(2, b-4, c+3, ...)
            b = 3: unreachable
      a mod 2 = 1:
        a ≥ 2: A(a, b, c, ...) --> A(2, a-2, b-2, c+3, ...)
        a = 1: unreachable
  b = 1: A(a, 1, c, d, ...) --> A(0, a+c+3, d, ...)
</pre>
</pre>


The TM starts in configuration A(0, 2, 0) after 7 steps.
=== References
 
[Category:BB(6)]]

Latest revision as of 10:46, 3 April 2026

List of incomplete pages:


1RB2LA1RC3RA_1LA2RA2RB0RC_1RZ3LC1RA1RB

{{machine|1RB2LA1RC3RA_1LA2RA2RB0RC_1RZ3LC1RA1RB} {{TM|1RB2LA1RC3RA_1LA2RA2RB0RC_1RZ3LC1RA1RB} is a non-halting BB(4,3) TM discovered by Pavel Kropitz in May 2023.<ref>https://discord.com/channels/960643023006490684/1095740122139480195/1113545691994783804</ref In April 2024, Shawn Ligocki showed the TM to follow an infinite pentational rule, proving it non-halting.<ref>https://discord.com/channels/960643023006490684/1095740122139480195/1230591736829575282</ref

Analysis by Shawn Ligocki

https://discord.com/channels/960643023006490684/1095740122139480195/1230591736829575282 

Let D(a, b, c, d, e) = 0^inf 1 2^a 1 3^b 1 01^c 1 2^d <A 2^2e+1 0^inf

Level 1: D(a, b, c, 2k+r, e)  ->  D(a, b, c, r, e+2k)
Level 2: D(a, b, c, 1, e)  ->  D(a, b, 0, 1, f2(c, e))
  where f2(c, e) = rep(λx -> 2x+5, c)(e)  ~= 2^c
Level 3: D(a, b, 0, 1, e)  ->  D(a, 0, 0, 1, f3(b, e))
  where f3(b, e) = rep(λx -> f2(x+2, 1), b)(e)  ~= 2^^b
Level 4: D(2a+r, 0, 0, 1, e)  ->  D(r, 0, 0, 1, f4(a, e))
  where f4(a, e) = rep(λx -> f3(2x+7), a)(e)  ~= 2^^^a
Level 5: D(0, 0, 0, 1, e)  ->  D(0, 0, 0, 1, f4(4e+19, f3(1, 1)))


where the last rule repeats forever.

=== References

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