1RB2LA1RA1RA 1LB1LA3RB1RZ: Difference between revisions

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Analysis: Added analysis by Pascal Michel
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It runs for 3,932,964 steps and leaves 2,050 ones.
It runs for 3,932,964 steps and leaves 2,050 ones.


== Analysis ==
== Analysis by Pascal Michel ==
To do
<pre>
Let C(n, 1) = . . . 0 (A0) 2^n 1 0 . . . ,
and C(n, 2) = . . . 0 (A0) 2^n 1 1 0 . . .
Then we have:
 
. . . 0 (A0) 0 . . . --( 6 )--> C(1, 2)
C(3k, 1) --( 15k^2 + 9k + 3 )--> C(5k + 1, 1)
C(3k + 1, 1) --( 15k^2 + 24k + 13 )--> . . . 0 1 3^(5k+2) 1 (H1) 0 . . .
C(3k + 2, 1) --( 15k^2 + 29k + 17 )--> C(5k + 4, 2)
C(3k, 2) --( 15k^2 + 11k + 3 )--> C(5k + 1, 2)
C(3k + 1, 2) --( 15k^2 + 21k + 7 )--> C(5k + 3, 1)
C(3k + 2, 2) --( 15k^2 + 36k + 23 )--> . . . 0 1 3^(5k+4) 1 (H1) 0 . . .
 
So we have:
 
. . . 0 (A0) 0 . . . --( 6 )-->
C( 1, 2 ) --( 7 )-->
C( 3, 1 ) --( 27 )-->
C( 6, 1 ) --( 81 )-->
C( 11, 1 ) --( 239 )-->
C( 19, 2 ) --( 673 )-->
C( 33, 1 ) --( 1,917 )-->
C( 56, 1 ) --( 5,399 )-->
C( 94, 2 ) --( 15,073 )-->
C( 158, 1 ) --( 42,085 )-->
C( 264, 2 ) --( 117,131 )-->
C( 441, 2 ) --( 325,755 )-->
C( 736, 2 ) --( 905,527 )-->
C( 1228, 1 ) --( 2,519,044 )-->
. . . 0 1 3^2047 1 (H1) 0 . . .
</pre>

Revision as of 12:25, 7 December 2025

1RB2LA1RA1RA_1LB1LA3RB--- (bbch) is the BB(2,4) champion. It was found in 2005 by Terry and Shawn Ligocki.

It runs for 3,932,964 steps and leaves 2,050 ones.

Analysis by Pascal Michel

Let C(n, 1) = . . . 0 (A0) 2^n 1 0 . . . ,
and C(n, 2) = . . . 0 (A0) 2^n 1 1 0 . . .
Then we have:

. . . 0 (A0) 0 . . . 	--( 6 )--> 	C(1, 2)
C(3k, 1) 	--( 15k^2 + 9k + 3 )--> 	C(5k + 1, 1)
C(3k + 1, 1) 	--( 15k^2 + 24k + 13 )--> 	. . . 0 1 3^(5k+2) 1 (H1) 0 . . .
C(3k + 2, 1) 	--( 15k^2 + 29k + 17 )--> 	C(5k + 4, 2)
C(3k, 2) 	--( 15k^2 + 11k + 3 )--> 	C(5k + 1, 2)
C(3k + 1, 2) 	--( 15k^2 + 21k + 7 )--> 	C(5k + 3, 1)
C(3k + 2, 2) 	--( 15k^2 + 36k + 23 )--> 	. . . 0 1 3^(5k+4) 1 (H1) 0 . . .

So we have:

. . . 0 (A0) 0 . . . --( 6 )-->
C( 1, 2 ) --( 7 )-->
C( 3, 1 ) --( 27 )-->
C( 6, 1 ) --( 81 )-->
C( 11, 1 ) --( 239 )-->
C( 19, 2 ) --( 673 )-->
C( 33, 1 ) --( 1,917 )-->
C( 56, 1 ) --( 5,399 )-->
C( 94, 2 ) --( 15,073 )-->
C( 158, 1 ) --( 42,085 )-->
C( 264, 2 ) --( 117,131 )-->
C( 441, 2 ) --( 325,755 )-->
C( 736, 2 ) --( 905,527 )-->
C( 1228, 1 ) --( 2,519,044 )-->
. . . 0 1 3^2047 1 (H1) 0 . . .