1RB1LD 1RC1RB 1LC1LA 0RC0RD: Difference between revisions
Combined introduction with link to bbch, reworded part of the introduction |
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{{machine|1RB1LD_1RC1RB_1LC1LA_0RC0RD}} | {{machine|1RB1LD_1RC1RB_1LC1LA_0RC0RD}} | ||
{{TM|1RB1LD_1RC1RB_1LC1LA_0RC0RD}} is the current [[Blanking Beaver]] BLB(4,2) champion, creating a blank tape after 32,779,477 steps. It was discovered and reported by Nick Drozd in 2021.<ref>Nick Drozd. [https://nickdrozd.github.io/2021/07/11/self-cleaning-turing-machine.html A New Record in Self-Cleaning Turing Machines]. 2021.</ref> | {{TM|1RB1LD_1RC1RB_1LC1LA_0RC0RD}} is the current [[Blanking Busy Beaver]] BLB(4,2) and [[Beeping Busy Beaver]] BBB(4,2) champion, creating a blank tape after 32,779,477 steps and [[Quasihalt|quasihalting]] after 32,779,478 steps at which point it becomes a [[translated cycler]] with period 1. It was discovered and reported by Nick Drozd in 2021.<ref>Nick Drozd. [https://nickdrozd.github.io/2021/07/11/self-cleaning-turing-machine.html A New Record in Self-Cleaning Turing Machines]. 2021.</ref> | ||
== Analysis by [[User:sligocki|Shawn Ligocki]] == | == Analysis by [[User:sligocki|Shawn Ligocki]] == | ||
Let <math display="block">D(a, b) = 0^\infty \; 1^a \; 0^b \; \textrm{D>} \; 0^\infty</math>then:<math display="block">\begin{array}{lc} | Let <math display="block">D(a, b):= 0^\infty\;1^a\;0^b\;\textrm{D}\textrm{>}\;0^\infty</math>then:<math display="block">\begin{array}{lc} | ||
D(a+3, & b) & \to & D(a, b+5) \\ | D(a+3, & b) & \to & D(a, b+5) \\ | ||
D(0, & b) & | D(0, & b) & \to & \text{Blank} \\ | ||
D(1, & b) & \to & D(b+2, 4) \\ | D(1, & b) & \to & D(b+2, 4) \\ | ||
D(2, & b) & \to & D(b+3, 4) \\ | D(2, & b) & \to & D(b+3, 4) \\ | ||
\end{array}</math>let <math>D(a) = D(a, 4)</math>, then we can simplify to: | \end{array}</math>let <math>D(a):= D(a, 4)</math>, then we can simplify to: | ||
<math display="block">\begin{array}{lc} | <math display="block">\begin{array}{lc} | ||
D(3k ) & \to & \ | D(3k ) & \to & \text{Blank} \\ | ||
D(3k+1) & \to & D(5k+6) \\ | D(3k+1) & \to & D(5k+6) \\ | ||
D(3k+2) & \to & D(5k+7) \\ | D(3k+2) & \to & D(5k+7) \\ | ||
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& \to & D(7) & \to & D(16) & \to & D(31) & \to & D(56) & \to & D(97) \\ | & \to & D(7) & \to & D(16) & \to & D(31) & \to & D(56) & \to & D(97) \\ | ||
& \to & D(166) & \to & D(281) & \to & D(472) & \to & D(791) & \to & D(1322) \\ | & \to & D(166) & \to & D(281) & \to & D(472) & \to & D(791) & \to & D(1322) \\ | ||
& \to & D(2207) & \to & D(3682) & \to & D(6141) & \to & \ | & \to & D(2207) & \to & D(3682) & \to & D(6141) & \to & \text{Blank} \\ | ||
\end{array} </math>which has the remarkable luck of applying this [[Collatz-like]] map 14 times before reaching the blanking config (expected # of applications before halting is 3). | \end{array} </math>which has the remarkable luck of applying this [[Collatz-like]] map 14 times before reaching the blanking config (expected # of applications before halting is 3). | ||
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== Relation to other machines == | == Relation to other machines == | ||
The map and trajectory are equivalent to that of the [[BB(5) champion]]. For all <math>k</math>, let <math>f(k)</math> be the number such that <math>D(k)\to D(f(k))</math>, or <math>\text{HALT}</math> if <math>D(k)\to\ | The map and trajectory are equivalent to that of the [[BB(5) champion]]. For all <math>k</math>, let <math>f(k)</math> be the number such that <math>D(k)\to D(f(k))</math>, or <math>\text{HALT}</math> if <math>D(k)\to\text{Blank}</math>, and let <math>g</math> be the map simulated by the BB(5) champion. Then: | ||
<math display="block">\begin{array}{lc} | <math display="block">\begin{array}{lc} |
Latest revision as of 22:52, 7 October 2025
1RB1LD_1RC1RB_1LC1LA_0RC0RD
(bbch) is the current Blanking Busy Beaver BLB(4,2) and Beeping Busy Beaver BBB(4,2) champion, creating a blank tape after 32,779,477 steps and quasihalting after 32,779,478 steps at which point it becomes a translated cycler with period 1. It was discovered and reported by Nick Drozd in 2021.[1]
Analysis by Shawn Ligocki
Let then:let , then we can simplify to:
Starting from (at step 19) we get the trajectory:
which has the remarkable luck of applying this Collatz-like map 14 times before reaching the blanking config (expected # of applications before halting is 3).
See also, previous analysis in 2021: https://www.sligocki.com/2021/07/17/bb-collatz.html
Relation to other machines
The map and trajectory are equivalent to that of the BB(5) champion. For all , let be the number such that , or if , and let be the map simulated by the BB(5) champion. Then:
So the size of this machine's BLB output is tied to the size of the BB(5) champion's output.
References
- ↑ Nick Drozd. A New Record in Self-Cleaning Turing Machines. 2021.