0RB1LD 1LC1RB 1LD1RE 1LA1LE 1LZ0RC: Difference between revisions

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Created page with "{{machine|0RB1LD_1LC1RB_1LD1RE_1LA1LE_1LZ0RC}} {{TM|0RB1LD_1LC1RB_1LD1RE_1LA1LE_1LZ0RC}} is the num(5) champion (the BB(5) TM which halts leaving the most consecutive ones on the tape) according to Andrés Sancho. It halts after 15590 steps with tape <math>0^\infty <Z 1^{165} 0^\infty</math> == Analysis by Shawn Ligocki == <pre> A(a, b) = $ 1^a <A 11^b $ A(a+3, b) -> A(a, b+2) A(0, b) -> A(2b, 1) A(1, b) -> A(0, b+1) A(2, b) -> $ <Z 1^{..."
 
Fix halting tape
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{{TM|0RB1LD_1LC1RB_1LD1RE_1LA1LE_1LZ0RC}} is the [[Busy Beaver Functions|num]](5) champion (the [[BB(5)]] TM which halts leaving the most consecutive ones on the tape) according to Andrés Sancho. It halts after 15590 steps with tape
{{TM|0RB1LD_1LC1RB_1LD1RE_1LA1LE_1LZ0RC}} is the [[Busy Beaver Functions|num]](5) champion (the [[BB(5)]] TM which halts leaving the most consecutive ones on the tape) according to Andrés Sancho. It halts after 15590 steps with tape


<math>0^\infty <Z 1^{165} 0^\infty</math>
<math display="block">0^\infty <Z \; 1^{165} \; 0^\infty</math>


== Analysis by Shawn Ligocki ==
== Analysis by Shawn Ligocki ==

Revision as of 00:21, 9 February 2025


0RB1LD_1LC1RB_1LD1RE_1LA1LE_1LZ0RC (bbch) is the num(5) champion (the BB(5) TM which halts leaving the most consecutive ones on the tape) according to Andrés Sancho. It halts after 15590 steps with tape

0<Z11650

Analysis by Shawn Ligocki

A(a, b) = $ 1^a <A 11^b $

A(a+3, b) -> A(a, b+2)
A(0, b) -> A(2b, 1)
A(1, b) -> A(0, b+1)
A(2, b) -> $ <Z 1^{2b+3} $

A(3k,   1) -> A(4k+2, 1)
A(3k+1, 1) -> A(4k+4, 1)
A(3k+2, 1) -> $ <Z 1^{4k+5} $

@13: A(3, 1)

Trajectory of "a" values starting from A(3, 1):
3 6 10 16 24 34 48 66 90 122 Halt(165)